(q^2-5q-15)/(q^2-10)

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Solution for (q^2-5q-15)/(q^2-10) equation: 


D( q )

q^2-10 = 0

q^2-10 = 0

q^2-10 = 0

1*q^2 = 10 // : 1

q^2 = 10

q^2 = 10 // ^ 1/2

abs(q) = 10^(1/2)

q = 10^(1/2) or q = -10^(1/2)

q in (-oo:-10^(1/2)) U (-10^(1/2):10^(1/2)) U (10^(1/2):+oo)

(q^2-(5*q)-15)/(q^2-10) = 0

(q^2-5*q-15)/(q^2-10) = 0

q^2-5*q-15 = 0

q^2-5*q-15 = 0

DELTA = (-5)^2-(-15*1*4)

DELTA = 85

DELTA > 0

q = (85^(1/2)+5)/(1*2) or q = (5-85^(1/2))/(1*2)

q = (85^(1/2)+5)/2 or q = (5-85^(1/2))/2

(q-((5-85^(1/2))/2))*(q-((85^(1/2)+5)/2)) = 0

((q-((5-85^(1/2))/2))*(q-((85^(1/2)+5)/2)))/(q^2-10) = 0

( q-((5-85^(1/2))/2) )

q-((5-85^(1/2))/2) = 0 // + (5-85^(1/2))/2

q = (5-85^(1/2))/2

( q-((85^(1/2)+5)/2) )

q-((85^(1/2)+5)/2) = 0 // + (85^(1/2)+5)/2

q = (85^(1/2)+5)/2

q in { (5-85^(1/2))/2, (85^(1/2)+5)/2 }

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